Question

1. A survey of households in a small town showed of 2,197 sampled households, that in 862 households at least one member attended a town meeting during the year. Using the 99% level of confidence, what is the confidence interval for the proportion of households represented at a town meeting?

A [0.3655, 0.4192]

B [0.3728, 0.4119]

C [0.3719, 0.4128]

D [0.3752, 0.4095]

2.

The mean of a normal distribution is 412 pounds. The standard deviation is 14 pounds. What is the area between 419 pounds and the mean of 412 pounds?

A 0.1341

B 0.3830

C 0.0958

D 0.1915

Answer 1

1)

Given :

x=862

n=2197

P^ = (x/n) = (862/2197)

Here using ti-83 calculator.

99% confidence interval for population proportion p is,

"A" : (0.3655 , 0.4192).

2)