A wholesaler has recently developed a computerized sales invoicing system. Prior to implementing this system, a manual system was used. Historically, the manual system produced 87% of invoices with 0 errors, 8% of invoices with 1 error, 3% of invoices with 2 errors, 1% of invoices with 3 errors, and 1% of invoices with more than 3 errors.
After implementation of the computerized system, a random sample of 500 invoices showed 479 invoices with 0 errors, 10 invoices with 1 error, 8 invoices with 2 errors, 2 invoices with 3 errors, and 1 invoice with more than 3 errors.
Tasks:
Create appropriate null and alternative hypotheses.
Justify the appropriate chi-square test to determine whether the error percentages for the computerized system differ from the normal system.
The chi-square statistic and p-values are 35.22 and < 0.0001. Interpret the p value for an accept/reject decision regarding the hypothesis. Choose the standard level of significance.
State your conclusion.
H0: If the data is consistent with specified distribution
Ha: If the data is not consistent
df= (r-1) = 4
let assume:
Critical value:
Test statistic:
Expected value(E) = Proportion* Sample
Invoice | Probability | Sample | Expected | (O-E)^2 | (O-E)^2/E |
0 | 0.87 | 479 | 435 | 1936 | 4.450575 |
1 | 0.08 | 10 | 40 | 900 | 22.5 |
2 | 0.03 | 8 | 15 | 49 | 3.266667 |
3 | 0.01 | 2 | 5 | 9 | 1.8 |
3+ | 0.01 | 1 | 5 | 16 | 3.2 |
Sum | 35.21724 |
The test statistic is significant at significant level 0.05 and Rejects H0. There is enough evidence to support the claim that the data is different from population proportion.
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