X |
5 |
6 |
7 |
8 |
P(X) |
1/16 |
5/8 |
1/4 |
1/16 |
i.
Is this probability distribution of random variable X valid or legitimate? Explain?
ii.
iii.
Find the expected value (μ) of this distribution.
Find the standard deviation (σ) of thisdistribution.
i)
This is valid probability distribution when P(X) = 1
Now,
P(X) = 1/16 + 5/8 + 1/4 + 1/16 = 1
Therefore, this is valid probability distribution.
b)
E(X) = X * P(X)
= 5 * 1/16 + 6 * 5/8 + 7 * 1/4 + 8 * 1/16
= 6.3125
c)
Standard deviation = X2 * P(X) - [ E(X)]2
= [ 52 * 1/16 + 62 * 5/8 + 72 * 1/4 + 82 * 1/16 ] - 6.31252
= 0.6818
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