Question

The following three independent random samples are obtained from three normally distributed populations with equal variance. The dependent variable is starting hourly wage, and the groups are the types of position (internship, co-op, work study).

Group 1: Internship	Group 2: Co-op	Group 3: Work Study
11	9.25	9.5
11.25	11	11.25
9.25	12.25	12.5
10	12.5	11
11.25	10.5	13.75
8.5	11	9.25
12	12.25	11.75
11.5	12.75	11
10.5	12.75	13
9.75	12.25	12
10.5	10.75	10.75

Use technology to conduct a one-factor ANOVA to determine if the group means are equal using ?=0.01.

Group means (report to 2 decimal places):
Group 1: Internship:    
Group 2: Co-op:    
Group 3: Work Study:    


ANOVA summary statistics:
F-ratio =  
(report accurate to 3 decimal places)
p=
(report accurate to 4 decimal places)

Conclusion:

The sample data suggest the average starting hourly wages are not the same.

There is not sufficient data to conclude the starting wages are different for the different groups.

Answer 1

The statistical software output for this problem is:

Analysis of Variance results:
Data stored in separate columns.

Column statistics

Column	n	Mean	Std. Dev.	Std. Error
Group 1: Internship	11	10.5	1.0488088	0.31622777
Group 2: Co-op	11	11.568182	1.1351812	0.34227001
Group 3: Work Study	11	11.431818	1.3697213	0.4129865

ANOVA table

Source	DF	SS	MS	F-Stat	P-value
Columns	2	7.4356061	3.717803	2.6152411	0.0898
Error	30	42.647727	1.4215909
Total	32	50.083333

Hence,

Group means:

Internship: 10.5

Co-op: 11.57

Work study: 11.43

F-ratio = 2.615

p = 0.0898

There is not sufficient data to conclude the starting wages are different for the different groups.