Let -y represent the mean CO level for the company's fleet.
ans a)
mean of y-bar = mean of y = 2.405g/mi
std of y-bar or standard error(s.e) = 0.7/sqrt(60) =
0.0904
ans b) at y bar = 2.5
z2.5 =( 2.5 - 2.405 ) /0.0904 = 1.051
at y bar = 2.7
z2.7 =( 2.7 - 2.405 ) /0.0904 =3.26
P ( 1.051 < z < 3.26 ) = normalcdf (1.051, 3.26 ,0,1) = 0.1463
the probability that y overbary is between 2.5 and 2.7 g/mi is 0.1463
ans c ) we know that invnorm(0.95,0,1) =1.645
z 0.05 =( y - 2.405) / 0.0904
1.645 * 0.0904 = y - 2.405
0.14871+2.405 =y
y= 2.554
There is only a 5% chance that the fleet's mean CO level is greater than 2.554g/mi
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