Question

Smith is a weld inspector at a shipyard. He knows from keeping track of good and substandard welds that for the afternoon shift 5% of all welds done will be substandard. If Smith checks 300 of the 7500 welds completed that shift, what is the probability that he will find between 10 and 20substandard welds? A)0.2033 B)0.6377 C)0.8132 D)0.4066

P (   10   ≤ X ≤    20   )  
Z1 =   (X1 - µ ) / σ =   -1.32   
Z2 =   (X2- µ ) / σ =   1.32   
                  
P (    -1.32 ≤ Z ≤   1.32 )   
= P ( Z ≤   1.325   ) - P ( Z ≤   -1.325   ) = 0.8132 (answer) NEED HELP EXPLAINING HOW TO GET THAT! WHERE IS THE 1.32 FROM?

Answer 1

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