A certain financial services company uses surveys of adults age 18 and older to determine if personal financial fitness is changing over time. A recent sample of 1,000 adults showed 410 indicating that their financial security was more than fair. Suppose that just a year before, a sample of 800 adults showed 280 indicating that their financial security was more than fair. What is the 95% confidence interval estimate of the difference between the two population proportions? (Round your answers to four decimal places.)
The statistical software output for this problem is:
Hence,
95% confidence interval will be:
(0.0150, 0.1050)
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