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What proportion of Z-scores are outside the interval Z = −3.08 and Z = 3.08? Round...

What proportion of Z-scores are outside the interval Z = −3.08 and Z = 3.08?

Round to 4 decimal places

Math   Statistics-And-Probability   
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Answer #1

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We can use the property of symmetry of the normal distribution for this.

We have been asked to calculate P(Z < -3.08 OR Z > 3.08) = ?

Since normal distribution is symmetrical P(Z<-3.08) = P(Z>3.08

So,

P(Z < -3.08 OR Z > 3.08) = 2*P(Z < -3.08)

= 2*0.001035

[Look up the Z table for Z = -3.08, you will get .001035]

= 0.00207 or .0021

Answer: 0.0021

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