Question

Consider the following hypothesis test for the mean difference. (Give your answers correct to four decimal places.)

(a) Determine the p-value for H_o: μ_d = 0 and H_a: μ_d > 0, with n = 19 and t = 1.97.


(b) Determine the p-value for H_o: μ_d = 0 and H_a: μ_d ≠ 0, with n = 22 and t = -1.81.


(c) Determine the p-value for H_o: μ_d = 0 and H_a: μ_d < 0, with n = 26 and t = -2.68.


(d) Determine the p-value for H_o: μ_d = 0.75 and H_a: μ_d > 0.75, with n = 13 and t = 3.54.

You may need to use the appropriate table in Appendix B to answer this question.

Answer 1

Answer :

(A). now we need to find out the p-value..?

now we using the p-value calculator also

given data :-

H_o: μ_d = 0 and H_a: μ_d > 0

n = 19

t = 1.97

This is a one tailed test.

Using a t table,

df = 19 - 1

= 18

TDIST(1.97,18,1)

p = 0.030006

(B). H_o: μ_d = 0 and H_a: μ_d ≠ 0

n = 22

t = -1.80

This is a one tailed test. Using a t table,

df = 26 - 1

= 25

TDIST(-1.81,25,1)

p = 0.006839

(C). H_o: μ_d = 0 and H_a: μ_d < 0

n = 26

t = -2.68

This is a one tailed test. Using a t table

df = 26 - 1

= 25

TDIST(-2.68,25,1)

p = 0.006419

(D).  H_o: μ_d = 0.75 and H_a: μ_d > 0.75

n = 13

t = 3.54

This is a one tailed test

Using a t table,

df = 13 - 1

= 12

TDIST(3.54,12,1)

p = 0.003543