Assume X is normally distributed with a mean of 4.3 and a
standard deviation of 6. Determine the value for x that solves each
of the following. Round the answers to 2 decimal places.
a) P(X<x)=0.95
Given,
= 4.3 , = 6
We convert this to standard normal as
P( X < x) = P( Z < x - / )
We have to calculate x such that
P( X < x) = 0.95
That is
P( Z < x - / ) = 0.95
From Z table, z-score for the probability of 0.95 is 1.645
x - / = 1.645
x - 4.3 / 6 = 1.645
Solve for x
x = 14.17
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