A company collected the ages from a random sample of its middle
managers, with the resulting frequency distribution shown
below.
Class Interval |
Frequency | |
20 to < 25 | 8 | |
25 to < 30 | 6 | |
30 to < 35 | 5 | |
35 to < 40 | 12 | |
40 to < 45 | 15 | |
45 to < 50 | 7 | |
What is the relative frequency for the class with the greatest frequency?
To calculate relative frequency we will divide the respective frequency by total frequency
For the given table
Class Interval |
Frequency | |
20 to < 25 | 8 | |
25 to < 30 | 6 | |
30 to < 35 | 5 | |
35 to < 40 | 12 | |
40 to < 45 | 15 | |
45 to < 50 | 7 |
Total frequency is = 8 + 6 + 5 + 12 + 15 + 7 = 53
relative frequency for the class with the greatest frequency = greatest frequency / total frequency
greatest frequency = 15
total frequency = 53
relative frequency for the class with the greatest frequency = 15/53 = 0.28301
relative frequency for the class with the greatest frequency = 0.283
E is the correct option.
Get Answers For Free
Most questions answered within 1 hours.