A simple random sample of 29 filtered 100-mm cigarettes is obtained from a normally distributed population, and the tar content of each cigarette is measured. The sample has a standard deviation of 0.220.22mg. Use a 0.05 significance level to test the claim that the tar content of filtered 100-mm cigarettes has a standard deviation different from 0.35 mg, which is the standard deviation for unfiltered king-size cigarettes. Complete parts (a) through (d) below.
a) find the test statistic.
b) find the p-value of the test statistic
given data are:-
sample size (n) = 29
sample sd (s) = 0.22
hypothesized sd () = 0.35
level of significance () = 0.05
hypothesis:-
a).test statistic be:-
degrees of freedom = (n-1) = (29-1) = 28
b).p value = 0.0035
[ using minitab for df = 28, chi square = 11.063, both tailed test]
you can also use p value calculator .
decision:-
p value = 0.0035 < 0.05
so, we reject the null hypothesis.
we conclude that,
there is sufficient evidence at 0.05 significance level to claim that the tar content of filtered 100-mm cigarettes has a standard deviation different from 0.35 mg
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