5 cards have been removed from a standard deck of cards. The cards are a 5 of Hearts, a 3 of Diamonds, a 4 of clubs, and a 6 of spades. What is the probability of getting the following play of cards: full house, flush and straight.
Hello Sir/Mam
5 cards are removed and 4 of them are HEARTS-5, DIAMOND-3, CLUB-4, SPADES-6.
On withdrawing of the fifth card, the following probabilities can be established:
(a) Full House : 0
Full house is established if the hand contains 3 cards of one rank and 2 of another. As it is not possible in any way given the above cards. hence its probability is 0.
(b) Flush : 0
Flush is established if the hand contains 5 cards of same suit. As it is not possible in any way given the above cards. hence its probability is 0.
(c) Straight : 16.67%
A straight is established if the hand contains 5 cards of sequential rank. We alreay have 3,4,5 and 6. We can get a straight by getting a 2 or a 7.
Hence,
I hope this solves your doubt.
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