Question

Is this correct? My claims is that 30% of coffee drinkers consume more than 1 cup of coffee per day. I asked 30 people if they consume more than 1 cup of coffee per day and 14 people stated they consume more than 1 cup of coffee per day.

1. Make a claim.

30% of coffee drinkers drunk more than 1 cup of coffee per day

2. Check the conditions and see if the requirements are met.

H0: p =0.30

Ha: p >0.30

Significance level = .05

Critical value = 1.960

N=30

X=14

Right tailed p-value

Np>5 and nq>5

Use: Z test for population proportion

3. Write out the calculator command that you were using and the result.

Stat->test->1-propZ test:

Po: .30

X=14

N=30

>Po

Calculate

Results:

Z= 1.992047

P=.023218

p̂=.466

n=30

4 Write a conclusion without using complicated wordings.

P ≤ α

.023 ≤.05

Reject the null hypothesis, there is sufficient evidence that the alternative hypothesis is true at a 95% confidence level. The evidence suggests that more than 30% of people consume more than 1 cup of coffee per day.

Answer 1

Please don't hesitate to give a "thumbs up" in case you're satisfied with the answer

Yes, you are correct. please read on in full.

1. Claim is correct
2. Claim should come always as the alternative hypothesis, which is correct in this case
3. Righly defined right t-test.
3. The calculator command is correct.
4. p-value = .0232
5. The p-value is less than .05 ( significance level assumed in the question), which means that
the null hypothesis is rejected and we "Accept" the alternative hypothesis . i.e. Claim is TRUE

i.,e. YES, 30% of coffee drinkers drunk more than 1 cup of coffee per day