Find a 90% confidence interval for a population mean ? for these values. (Round your answers to three decimal places.)
(a)
n = 130, x = 0.85, s2 = 0.084
to
(b)
n = 40, x = 20.1, s2 = 3.86
to
(c)
Interpret the intervals found in part (a) and part (b).
There is a 10% chance that an individual sample proportion will fall within the interval.In repeated sampling, 10% of all intervals constructed in this manner will enclose the population proportion. In repeated sampling, 90% of all intervals constructed in this manner will enclose the population mean.90% of all values will fall within the interval.There is a 90% chance that an individual sample proportion will fall within the interval.
a) At 90% confidence interval the critical value is t* = 1.657
The 90% confidence interval for population mean is
+/- t* * sqrt(s2/n)
= 0.85 +/- 1.657 * sqrt(0.084/130)
= 0.85 +/- 0.042
= 0.808, 0.892
b) At 90% confidence interval the critical value is t* = 1.685
The 90% confidence interval for population mean is
+/- t* * sqrt(s2/n)
= 20.1 +/- 1.685 * sqrt(3.86/40)
= 20.1 +/- 0.523
= 19.577, 20.623
c) In repeated sampling, 90% of all intervals constructed in this manner will enclose the population mean.
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