A normal random variable x has mean ? = 1.7 and standard deviation ? = 0.12. Find the probability associated with each of the following intervals. (Round your answers to four decimal places.)
(a)
1.00 < x < 1.40
(b)
x > 1.34
(c)
1.25 < x < 1.50
a) P(1 < X < 1.4)
= P((1 - )/ < (X - )/ < (1.4 - )/)
= P((1 - 1.7)/0.12 < Z < (1.4 - 1.7)/0.12)
= P(-5.83 < Z < -2.5)
= P(Z < -2.5) - P(Z < -5.83)
= 0.0062 - 0
= 0.0062
b) P(X > 1.34)
= P((X - )/ > (1.34 - )/)
= P(Z > (1.34 - 1.7)/0.12)
= P(Z > -3)
= 1 - P(Z < -3)
= 1 - 0.0013
= 0.9987
c) P(1.25 < X < 1.5)
= P((1.25 - )/ < (X - )/ < (1.5 - )/)
= P((1.25 - 1.7)/0.12 < Z < (1.5 - 1.7)/0.12)
= P(-3.75 < Z < -1.67)
= P(Z < -1.67) - P(Z < -3.75)
= 0.0475 - 0
= 0.0475
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