Question

The probability of a potential employee passing a training course is 86%. If you selected 15 potential employees and gave them the training course, what is the probability that 11 or less will pass the test?

Answer 1

Solution :

Given that,

p = 0.86

q = 1 - p =1 - 0.86 = 0.14

n = 15

Using binomial distribution,

= n * p = 15 * 0.86 =12.9

= n * p * q = 15 *0.86 *0.14 =1.3439

Using continuity correction ,

P(x >11 ) = 1 - P(x < 11.5)

= P((x - ) / < (11.5- 12.9) / 1.3439)

= P(z < -1.0417)

ANSWER    =0.1488