Suppose that about 9.5% of the population is left-handed. A 200-seat school auditorium has been built with 15 “lefty seats,” seats that have the built-in desk on the left rather than the right arm of the chair. What is the largest number of students that can sit in the auditorium and still have enough seats for left-handed students? Explain how you arrived at your answer.
Max left handed person that can sit in the auditorium = 15
So we need to find maximum students that can sit in the auditorium where no of left handed students ≤ 15.
proportion of left handed students = 9.5%
Let no of students that can sit in the auditorium where no of left handed students ≤ 15 be X
Hence, X * 9.5% ≤ 15
X ≤ 15 / 9.5%
X ≤ 157.89
ANS: Largest number of students that can sit in the auditorium and still have enough seats for left-handed students = 157
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