Question

Information on a packet of seeds claims that the germination rate is 92%. What’s the probability that more than 95% of the 200 seeds in the packet will germinate?

Answer 1

Here n = 200, p = probability of germination = 0.92

n*p*(1-p) = 14.72 > 10

So we can use normal approximation to find the probability

Here we want to find

.....( 1)

Mean of is 0.92 and standard deviation of

Let's use excel :

= 0.9411

Plug this value in equation ( 1 ), we get:

So final answer is 0.0589