Question
An engineer measure 4 different pressures, 90, 98, 95 and 99 psi. What is the standard...
An
engineer measure 4 different pressures, 90, 98, 95 and 99 psi. What
is the standard deviation of these measurments?
Homework Answers
Answer #1
The measurements are 90 , 98 , 95 and 99 psi. We have to find
the mean 
first.
= 
x / n
= (90 + 98 + 95 + 99) / 4
= 95.5
The standard deviation =
{
(x -
)2/ n}
=
(49/4)
=(12.25)
= 3.5
standard deviation = 3.5 psi
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