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Q1) A cross is made between a pea plant homozygous for two recessive mutations (aabb) and...

Q1) A cross is made between a pea plant homozygous for two recessive mutations (aabb) and a wild-type plant (AABB). The F1 progeny are crossed to a doubly mutant plant (aabb) and the following individuals are observed in the progeny.

Number           Phenotype

280                  Wild-type

270                  Both mutant phenotypes

220                  Mutant phenotype a only

230                  Mutant phenotype b only

Using the hypothesis that these genes are unlinked, what is the value of chi squared for these data?

a) 3.6 b) 100 c) 10.4 d) 1.6

Q2) For the data from Question 3, which value of Chi squared represents the threshold to use when deciding if the data fit the hypothesis with 95% confidence?

a) 0.35 b) 3.84 c) 0.04 d) 7.81

Q3) Based on your answers to Questions 3 and 4, should you conclude that genes a and b are linked or unlinked?

a) Unlinked, because calculated value of Chi squared is less than the value from the table, so accept hypothesis that they are unlinked.

b) Uninked, because calculated value of Chi squared is higher than the value from the table, so accept hypothesis that they are unlinked.

c) Linked, because calculated value of Chi squared is less than the value from the table, so reject hypothesis that they are unlinked.

d) Linked, because calculated value of Chi squared is higher than value from the table, so reject hypothesis that they are unlinked.

Math   Statistics-And-Probability   
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