A manufacturer randomly tests 150 items off of its assembly line and finds that 9 are defective. What is the lower bound for a 95% confidence interval for the proportion of all defective items produced of that assembly line? Round to at least 3 decimal places.
Solution :
Given that,
n = 150
x = 9
Point estimate = sample proportion = = x / n = 9 / 150 = 0.06
1 - = 1 - 0.06 = 0.94
At 95% confidence level the z is,
= 1 - 95%
= 1 - 0.95 = 0.05
Z = Z 0.05 = 1.645
Margin of error = E = Z * (( * (1 - )) / n)
= 1.645 * (((0.06 * 0.94 ) / 150)
= 0.032
A 95% Lower bound confidence interval for population proportion p is ,
- E
0.06 - 0.032 = 0.028
Lower bound = 0.028
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