A random sample of small-business managers was given a leadership style questionnaire. The results were scaled so that each manager received a score for initiative. Suppose the following data are a random sample of these scores.
43 | 42 | 41 | 39 | 38 | 31 | 41 |
43 | 35 | 45 | 30 | 33 | 35 | 44 |
36 | 43 | 39 | 33 | 39 | 41 | 41 |
33 | 35 | 36 | 41 | 33 | 43 | 38 |
41 | 42 | 44 | 35 | 36 | 33 | 38 |
32 | 30 | 43 | 42 |
Assuming σ is 3.891, use these data to construct a 90%
confidence interval to estimate the average score on initiative for
all small-business managers.
Appendix A Statistical Tables
(Round the intermediate values to 3 decimal places.
Round your answers to 3 decimal places.)
______ ≤ μ ≤ _______
Since population standard deviation is known, Use z-distribution.
43 | 42 | 41 | 39 | 38 | 31 | 41 |
43 | 35 | 45 | 30 | 33 | 35 | 44 |
36 | 43 | 39 | 33 | 39 | 41 | 41 |
33 | 35 | 36 | 41 | 33 | 43 | 38 |
41 | 42 | 44 | 35 | 36 | 33 | 38 |
32 | 30 | 43 | 42 |
Refer Standard normal table/Z-table or use excel function "=NORM.S.INV((1-0.05))" to find the Z-value. |
Get Answers For Free
Most questions answered within 1 hours.