Question

Exercise 5 For the study in Exercise 4, DNA samples were taken from dingoes in different...

Exercise 5

For the study in Exercise 4, DNA samples were taken from dingoes in different states

in Australia. In the state of Queensland, 356 samples were collected and 71 were

found to be purebred. In the state of South Australia, 148 samples were collected

and 47 were purebred.

(a) Estimate the difference in the proportion of dingoes that are purebred between

Queensland and South Australia. Be sure to use the appropriate method based on

the number of observations with and without the characteristic of interest.

(b) Calculate a 90% confidence interval for the difference in the proportion of purebred

dingoes between Queensland and South Australia. Be sure to use the appropriate

method based on the number of observations with and without the characteristic of

interest.

(c) Interpret the interval from Part (b) in words. Do you think there is a difference in

the proportion of purebred dingoes between Queensland and South Australia? Why

or why not?

Homework Answers

Answer #1

Exercise 5

In Queensland, 71 out of 356 samples are purebred

In South Australia, 47 out of 148 samples were purebred

n1 = 356

n2 = 148

a)

Proportion of dingoes in Queensland (p1) = 71/356 = 19.94%

Proportion of dingoes in South Australia (p2) = 47/148 = 31.75%

Difference between proportion of dingoes in Queensland and South Australia

= p1 – p2

= 19.94% - 31.75%

= -11.81%

Thus, it is estimated that the proportion of purebred dingoes in Queensland is less than the proportion of purebred dingoes in South Australia by 11.81%

b)

Conducting inference from the difference in proportions as it is a random sample that can be divided into two and interpreted independently.

Confidence interval is given as:

  • (p1 – p2) ± z* √ [p1(1 - p1)/ n1 + p1(1 - p1)/ n1] using z value for 90% confidence interval
  • -0.1181 ± 1.645 * √ (0.00191183)
  • -0.1181 ± 1.645 * 0.0437
  • -0.1181 ± 0.07192
  • (-0.19, -0.04618)

c)

Interpretation: We are 90% confident that the true value of the difference between the two population proportions lies between -0.19 and -0.04618.

Let Null hypothesis be that there is no difference in proportion of purebred dingoes between Queensland and South Australia. Based on the 90% confidence intervals, it can be concluded that there is a difference in the proportion of purebred dingoes between Queensland and South Australia because there is strong evidence against rejecting the null hypothesis.

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
To compare water quality from wells in two different areas, water samples were taken from 50...
To compare water quality from wells in two different areas, water samples were taken from 50 wells in the first area, tested, and 31 were found to meet standards. From the second area, 42 out of 60 wells were found to meet standards. Use the p-value method to test the claim that both areas have the same proportion of wells that meet standards at the 95% confidence level. Based on this result, does there appear to be a significant difference...
The following two samples were collected as matched pairs: Pair 1 2 3 4 5 6...
The following two samples were collected as matched pairs: Pair 1 2 3 4 5 6 7 8 Sample 1 8 4 6 9 9 7 9 8 Sample 2 5 7 6 5 6 9 7 6 a. State the null and alternative hypotheses to estimate the difference in means between the populations from which Samples 1 and 2 were drawn. b. Calculate the appropriate test statistic and interpret the results of the hypothesis test using α = 0.1....
Exercise 2. The following information is based on independent random samples taken from two normally distributed...
Exercise 2. The following information is based on independent random samples taken from two normally distributed populations having equal variances: Sample 1 Sample 2 n1= 15 n2= 13 x1= 50 x2= 53 s1= 5 s2= 6 Based on the sample information, determine the 90% confidence interval estimate for the difference between the two population means.
In a genetic inheritance study discussed by Margolin, blood was collected from samples of individuals from...
In a genetic inheritance study discussed by Margolin, blood was collected from samples of individuals from several ethnic groups, and mean sister chromatid exchange (MSCE) was measured for each individual. We wish to see if there's a difference in average MSCE for the groups labeled "Native American" and "Caucasian." Here's the data: Native American: 8.50, 9.48, 8.65, 8.16, 8.83, 7.76, 8.63 Caucasian: 8.27, 8.20, 8.25, 8.14, 9.00, 8.10, 7.20, 8.32, 7.70 a. What's the experimental unit? What measurements are taken...
Random samples of students at 122 ​four-year colleges were interviewed several times since 1995. Of the...
Random samples of students at 122 ​four-year colleges were interviewed several times since 1995. Of the students who reporteddrinking alcohol the percentage who reported bingeing at least three times within the past two weeks was 41.4​% of 333 students in 1995 and 21% of 841 students in 2007 a. Estimate the difference between the proportions in 2007and 1995​, interpret. b. Find the standard error for this difference. Interpret it. c. Define the two relevant population parameters to compare in the...
1) Independent random samples, each containing 90 observations, were selected from two populations. The samples from...
1) Independent random samples, each containing 90 observations, were selected from two populations. The samples from populations 1 and 2 produced 21 and 14 successes, respectively. Test H0:(p1?p2)=0 against Ha:(p1?p2)?0. Use ?=0.07. (a) The test statistic is (b) The P-value is (c) The final conclusion is A. We can reject the null hypothesis that (p1?p2)=0 and accept that (p1?p2)?0. B. There is not sufficient evidence to reject the null hypothesis that (p1?p2)=0. 2)Two random samples are taken, one from among...
1)Will listening to different forms of music affect average grades on exam? Two different groups were...
1)Will listening to different forms of music affect average grades on exam? Two different groups were studied - Rap and Mozart - with the following results: those who listened to Rap music while studying had z = 86.7, with Sx = 3.9 and n = 29 while those who listened to Mozart while studying had i = 85.6 with Sg = 3.2 and n = 20. Using this data, construct a 99% confidence interval for the difference between average grades...
UCF College of Business obtained the following results from two independent random samples on the salaries...
UCF College of Business obtained the following results from two independent random samples on the salaries of a recent graduating class: Sample Economics (1) Majors Sample Marketing (2) Majors Sample Size Economics Majors =36 Sample Size Marketing Majors =54 Mean Sample Economics = $51,230 Mean Sample Marketing =$49,300 Standard Deviation Sample Economics =$1,035 Standard Deviation Sample Marketing =$1,450 Managerial Report Prepare a managerial report that addresses the following issues: What is the degrees of freedom for the t distribution (round...
A study of iron deficiency among infants compared samples of infants following different feeding regimens. One...
A study of iron deficiency among infants compared samples of infants following different feeding regimens. One group contained breast-fed infants, while the infants in another group were fed a standard baby formula without any iron supplements. Here are summary results on blood hemoglobin levels at 12 months of age. Group n x s Breast-fed 24 13.1 1.7 Formula 18 12.6 1.8 Carry out a t test. Give the P-value. (Use α = 0.01. Use μbreast-fed − μformula. Round your value...
Where are the deer? Random samples of square-kilometer plots were taken in different ecological locations of...
Where are the deer? Random samples of square-kilometer plots were taken in different ecological locations of a national park. The deer counts per square kilometer were recorded and are shown in the following table. Mountain Brush Sagebrush Grassland Pinon Juniper 29 24 10 27 59 3 25 16 2 27 24 6 Shall we reject or accept the claim that there is no difference in the mean number of deer per square kilometer in these different ecological locations? Use a...