Question

a sample size of 50 with 34 successes was randomly selected. Create a CI with 90% confidence to target the population proportion

Answer #1

TOPIC:Confidence interval for the population proportion.

What is the p -value when the population proportion of successes
is 50% , the sample size is 65 , and the number of successes in the
sample is 30 if we believe that the population proportion of
successes is less than 50% ?
1. -1.382
2.-0.620
3. 0.268
4. None of the above

Create a 90% confidence interval about a sample proportion given
that the sample proportion is .61 and the sample size is 1250.

Given below are the number of successes and sample size for a
simple random sample from a population. x equals=6, n equals=40,
98% level
a. Determine the sample proportion.
b. Decide whether using the one-proportion z-interval procedure
is appropriate.
c. If appropriate, use the one-proportion z-interval procedure
to find the confidence interval at the specified confidence
level.
d. If appropriate, find the margin of error for the estimate of
p and express the confidence interval in terms of the sample...

Assume that a sample is used to estimate a population proportion
p. Find the 90% confidence interval for a sample of size 355 with
71 successes.

Below, n is the sample size, p is the population proportion of
successes, and X is the number of successes in the sample. Use the
normal approximation and the TI-84 Plus calculator to find the
probability. Round the answer to at least four decimal places.
n=76, p=0.41
P(28<X<38)=

31) – (33): A random sample of size n = 40 is selected from a
population that has a proportion of successes p = 0.8.
31) Determine the mean proportion of the sampling distribution
of the sample proportion.
32) Determine the standard deviation of the sampling
distribution of the sample proportion, to 3 decimal places.
33) True or False? The sampling distribution of the sample
proportion is approximately normal.

It was determined that the sample mean weight of 10 randomly
selected house cats was 8.4 pounds. We seek to create a 90%
confidence interval for the population mean weight of house cats in
the United States. The criteria n LaTeX: \le≤≤ .05N for
constructing a confidence interval for the population mean weight
of housecats is satisfied in this example. Group of answer choices
True False

Assume that a sample is used to estimate a population proportion
p. Find the 90% confidence interval for a sample of size 230 with
12% successes. Enter your answer as an open-interval (i.e.,
parentheses) using decimals (not percents) accurate to three
decimal places.

1,) Construct a 90% confidence interval for the population
proportion if an obtained sample of size n = 150 has x = 30
2.) Construct a 95% confidence interval for the population mean
if an obtained sample of size n = 35 has a sample mean of 18.4 with
a sample standard deviation of 4.5.

1.) A randomly selected sample of 70 casino patrons has an
average loss of $300 with a sample standard deviation of $100. Use
this information to complete the following:
a) Does the information above provide an estimate of a
population mean or a population proportion?
b) Provide a point estimate for the population mean loss of all
casino patrons.
c) Construct and interpret a 90% confidence interval for the
parameter you selected in part (a).
d) What is the margin...

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