The scores of students on an exam are normally distributed with a mean of 250 and a standard deviation of 40. (a) What is the first quartile score for this exam? (Recall that the first quartile is the value in a data set with 25% of the observations being lower.) Answer: (b) What is the third quartile score for this exam? Answer:
Given that,
mean = = 250
standard deviation = = 40
Using standard normal table,
P(Z < z) = 25%
=(Z < z) = 0.25
= P(Z < z ) = 0.25
z =-0.67
Using z-score formula
x = z +
x = -0.67*40+250
x = 223.2
b.
third quartile
Using standard normal table,
P(Z < z) = 75%
=(Z < z) = 0.75
= P(Z < z ) = 0.75
z =0.67
Using z-score formula
x = z +
x = 0.67*40+250
x = 276.8
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