Question

*M&M Mars* publishes information regarding the
proportions of colors of candies in each type of *M&Ms*
(plain, peanut, pretzel, caramel, etc.). The plain type
*M&Ms*are advertised to have 60% brown candies.

Suppose that 20 students each take a random sample of 50 candies, calculate the sample proportion of brown candies, and create a single graph from the class data.

Answer each of the questions by choosing the best responses from the options below. **You will choose one response for each question from the list below.

1) What are the observational units on the graph?

2) What is the variable on the horizontal axis of the graph?

a. Each candy is an observational unit on the graph.

b. Only the brown candies are observational units on the graph.

c. Each sample proportion is an observational unit on the graph.

d.The variable on the horizontal axis of the graph is whether or not the candy is brown.

e. The variable on the horizontal axis of the graph is "sample proportion of brown candies."

f. This data cannot be graphed.

Answer #1

**1)**

**b**. Only the brown candies are observational
units on the graph.

Because an observational unit is the object or entity whose characteristics are measured and here, we are measuring the characteristic (sample proportion) of brown candies.

**2)**

**e**. The variable on the horizontal axis of the
graph is "sample proportion of brown candies."

On X-axis (horizontal axis), we take sample proportion of brown candies.

On Y-axis (vertical axis), we take frequency of such proportions.

Example graph:

Total frequency =Total number of students =20

M&M Mars publishes information regarding the
proportions of colors of candies in each type of M&Ms
(plain, peanut, pretzel, caramel, etc.). The plain type
M&Msare advertised to have 60% brown candies.
Let's say you take a random sample of candies. Are you more
likely to get a sample with 60% brown candies if you have a sample
of 40 candies or a random sample of 400 candies?
a. A random sample of 40 M&Ms is more likely to
have 60%...

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sample of 40 peanut M&Ms contained 7 red candies. (Use p1 for
the proportion of red candies in plain M&Ms and p2 for the
proportion of red candies in peanut M&Ms.)
(a) Construct a 95% confidence interval for the difference in
the proportions of red candies...

Does the maker of M&Ms® (Mars, Inc.) use the same
proportion of red candies in its plain and peanut varieties? A
random sample of 51 plain M&Ms contained 11 red candies, and
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candies. (Use p1 for the proportion of red
candies in plain M&Ms and p2 for the
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Color
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Yellow
Red
Orange
Green
Blue
Brown
Percentage
23%
17%
23%
7%
9%
8%
13%
Suppose you have a large bag of plain M&M candies and you
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No. Choosing a green and blue M&M is...

M&M plain candies come in various colors. According to the
M&M/Mars Department of Consumer Affairs, the distribution of
colors for plain M&M candies is as follows.
Color
Purple
Yellow
Red
Orange
Green
Blue
Brown
Percentage
17%
18%
17%
9%
8%
10%
21%
Suppose you have a large bag of plain M&M candies and you
choose one candy at random.(a) Find P(green candy
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Yes. Choosing a green and blue M&M is not...

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M&M/Mars Department of Consumer Affairs, the distribution of
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Suppose you have a large bag of plain M&M candies and you
choose one candy at random. (a) Find P(green candy or blue candy).
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M&Ms are multicolored candies in a bag with six colors:
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Yellow
Red
Orange
Green
Blue
Percent
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20%
20%
10%
10%
10%
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for the mix of colors in their bags of plain chocolate
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Stated Distribution of Colors
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Yellow
Red
Orange
Green
Blue
Percent
30%
20%
20%
10%
10%
10%
Now, you randomly select 200 M&M's and get the counts given
in the table below. You expected about 20 blues but only got 9. You
suspect that the maker's claim is not true.
Observed Counts by Color...

M&M's Color Distribution: Suppose the
makers of M&M candies give the following average percentages
for the mix of colors in their bags of plain chocolate
M&M's.
Stated Distribution of Colors
Brown
Yellow
Red
Orange
Green
Blue
Percent
30%
20%
20%
10%
10%
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Now, you randomly select 200 M&M's and get the counts given
in the table below. You expected about 20 blues but only got 9. You
suspect that the maker's claim is not true.
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