Question

A new diagnostic test is created to assist in detection of a rare disease. During development,...

A new diagnostic test is created to assist in detection of a rare disease. During development, a study is conducted to evaluate the effectiveness of this new test. The test is run on 100 known cases and 200 controls. Results indicate that 90 of the cases yield positive tests, as do 30 of the controls.

07. The Positive Predictive Value for this test indicates that: A. The likelihood that a positive test result is predictive of disease is 30/120, or 25 % B. The likelihood that a positive test result is predictive of disease is 90/100, or 90% C. The likelihood that a positive test result is predictive of disease is 90/120, or 75% D. The likelihood that a positive test result is predictive of disease is 3 times greater (90/30) than the likelihood that a positive test result is predictive of no disease E. The likelihood that a positive test result is predictive of disease is 9 times greater (90/10) than the likelihood that a positive test result is predictive of no disease

08. If one extremely high score is added to a distribution of scores, what effect would it have on measures of central tendency? A. It will alter the mean to a greater extent than it will alter the median or mode B. It will alter the median to a greater extent than it will alter the mode or mean C. It will alter the mode to a greater extent than it will alter the median or mean D. It will have an equivalent effect on the mean, median, and mode E. It will have no effect on the mean, median, or mode

09. The probability of failing to reject the null hypothesis when the null hypothesis is false is known as: A. Power B. p-value C. Type I error D. Type II error

Homework Answers

Answer #1

Solution: 07. The Positive Predictive Value for this test indicates that:

Answer: .C. The likelihood that a positive test result is predictive of disease is 90/120, or 75%

08. If one extremely high score is added to a distribution of scores, what effect would it have on measures of central tendency?

Answer: A. It will alter the mean to a greater extent than it will alter the median or mode

09. The probability of failing to reject the null hypothesis when the null hypothesis is false is known as:

Answer: D. Type II error

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
8. In the population, there is no difference between men and women on a certain test....
8. In the population, there is no difference between men and women on a certain test. However, the mean for men was higher than the mean for women in your sample, and with a t of 4.532 and a p-value of .004, you have determined it is appropriate to reject the null hypothesis and conclude a difference does exist. What type of error did you make? A. Type I B. Type II C. You confirmed the null hypothesis. D. Standard...
The mean survival time for patients with a particular form of disease is 4 years. A...
The mean survival time for patients with a particular form of disease is 4 years. A new treatment is tried on 20 patients with this particular disease and their average survival time is 4.7 years with a standard deviation of 1.5 years. (a) State the direction of the alternative hypothesis to test if the new treatment constitutes a significant improvement in survival time. Type gt (greater than), ge (greater than or equal to), lt (less than), le (less than or...
Consider a manufacturer's claim that bricks produced by a new and more efficient process have amean...
Consider a manufacturer's claim that bricks produced by a new and more efficient process have amean compressive strength greater than 50.0 (measured in units of 100 pounds per square inch).Bricks that do not meet this standard are considered nonconforming and will not be used by thecustomer. From past experience, it is known that the mean compressive strength of bricks is normallydistributed with a standard deviation of 6. The bricks will not be accepted unless we can bereasonably sure that the...
Conduct a test of the null hypothesis that the mean height for all students in the...
Conduct a test of the null hypothesis that the mean height for all students in the Census at School database is equal to 155 cm vs the alternative that the mean Height is greater than 155 cm. Use a significance level of 0.05. a. State the null and alternative hypotheses. Ho: m = 155 Ha: m > 155 b. Provide the Statcrunch output table. Hypothesis test results: Variable Sample Mean Std. Err. DF T-Stat P-value Height 159.86 1.7311103 49 2.8074468...
Please assist me with steps 2, 3,and 5 Determine if there is sufficient evidence to conclude...
Please assist me with steps 2, 3,and 5 Determine if there is sufficient evidence to conclude the average amount of _Births_______________ is _______6000________________ in the United States and territories at the .05_ level of significance. Mean 6014.019 Standard Error 1028.863 Median 4055.5 Mode #N/A Standard Deviation 7419.235 Sample Variance 55045044 Kurtosis 12.5059 Skewness 3.182601 Range 42392 Minimum 444 Maximum 42836 Sum 312729 Count 52 Step 1: Clearly state a null and alternative hypothesis Ho: μ ≥ ≤ = 6000 Ha:...
1. An unstandardized test of aggression has a mean of 35.19. You take a sample of...
1. An unstandardized test of aggression has a mean of 35.19. You take a sample of 44 video game players and find their scores on this test have a mean of 39.84 and a standard deviation of 12.42. Are their aggression scores greater than the standard of 35.19? a. State the null and alternative hypotheses. b. Find your critical value(s) with a criterion of .01. Remember if the appropriate line is not available exactly in the table to pick the...
The gas mileage for a particular type of car is known to have a standard deviation...
The gas mileage for a particular type of car is known to have a standard deviation σ = 1 mile. For a fixed speed (65 miles/hour) sixteen cars were tested and found to get an average of 24.3 miles per gallon. What is the z-test statistic for the null hypothesis H0: μ = 25 miles per gallon? a. -.7        b. -1.4          c.   -2.8        d. 1.4 If the z-test statistic for H0: μ = 10 yields a p-value of .03. Should...
An observational study of Alzheimer's disease (AD) obtained data from 8 AD patients exhibiting moderate dementia...
An observational study of Alzheimer's disease (AD) obtained data from 8 AD patients exhibiting moderate dementia and selected a group of 6 control individuals without AD. AD is a progressive neurodegenerative disease of the elderly and advancing age is known to be a primary risk factor in AD diagnosis. Therefore, it was crucial for the study's credibility to examine whether the ages in the AD group might be significantly different than in the control group. The ages of the subjects...
An observational study of Alzheimer's disease (AD) obtained data from 12 AD patients exhibiting moderate dementia...
An observational study of Alzheimer's disease (AD) obtained data from 12 AD patients exhibiting moderate dementia and selected a group of 11 control individuals without AD. AD is a progressive neurodegenerative disease of the elderly and advancing age is known to be a primary risk factor in AD diagnosis. Therefore, it was crucial for the study's credibility to examine whether the ages in the AD group might be significantly different than in the control group. The ages of the subjects...
An observational study of Alzheimer's disease (AD) obtained data from 10 AD patients exhibiting moderate dementia...
An observational study of Alzheimer's disease (AD) obtained data from 10 AD patients exhibiting moderate dementia and selected a group of 7 control individuals without AD. AD is a progressive neurodegenerative disease of the elderly and advancing age is known to be a primary risk factor in AD diagnosis. Therefore, it was crucial for the study's credibility to examine whether the ages in the AD group might be significantly different than in the control group. The ages of the subjects...