Question

Treat the Patients dataset (Excel) as a sample from a larger population. Assuming that the total charges variable is normally distributed, use a one-tail t test of hypothesis (α = 0.05) for the mean (σ unknown) to test the hypothesis that the population mean total charges is greater than $10,000. Make sure you define the null and alternate hypotheses. Using the pooled variance t-test for the difference between two means, at the 0.05 level of significance, is there evidence that the mean age for male patients is different from the mean age for female patients? Be sure to provide the null and alternate hypotheses.

Total Chges $            5,418.85 $            4,575.10 $          12,031.18 $            3,617.84 $          12,806.88 $            5,295.55 $            3,453.21 $            1,760.03 $            3,290.40 $            6,253.65 $            3,896.16 $            1,795.35 $            9,265.17 $            3,282.90 $            9,565.83 $            3,782.15 $            6,384.28 $            4,904.25 $            4,169.92 $            5,204.41 $            6,740.00 $            5,016.44 $            4,178.94 $            4,105.26 $            4,717.30 $            6,598.92 $            1,633.85 $            2,200.85 $            7,461.54 $          11,413.23 $            5,607.55 $            4,850.62 $            7,102.49 $          13,615.69 $            5,069.18 $            6,536.07 $            7,401.25 $            3,744.34 $            8,653.68 $          14,423.21 $            3,742.30 $            5,514.09 $            7,390.15 $            9,358.20 $          14,570.29 $            4,526.43 $            6,846.77 $            2,927.62 $            4,404.13 $            8,056.36 $          10,703.34 $          16,458.95 $            4,770.10 $          15,282.57 $          10,105.30 $            7,871.29 $            3,411.10 $          10,962.17 $            7,374.27 $            7,788.51 $            8,191.10 $          11,117.35 $            5,624.54 $            4,574.92 $            3,644.36 $            2,937.92 $            3,944.78 $            6,366.10 $            4,992.01 $            6,929.35 $            5,595.42 $            3,466.70 $            7,289.77 $            6,375.95 $            3,585.62 $            5,970.45 $          10,578.14 $            2,223.60 $            2,250.50 $            1,644.55 $            2,491.45 $            1,691.50 $            7,931.92 $            5,121.97 $            6,940.75 $          12,088.08 $            2,325.60 $            4,452.78 $            6,157.43 $          21,474.90 $            8,566.51 $            4,910.27 $            3,275.03 $          12,080.81 $            7,436.85 $          15,624.20 $            4,590.48 $            3,232.63 $            3,768.11 $            9,862.26 $          10,626.42 $            6,967.99 $            5,891.25 $            4,756.91 $            8,096.93 $            4,620.59 $            5,796.49 $            1,483.39 $            2,510.05 $          10,185.83 $            3,391.90 $            8,418.13 $            4,346.47 $            2,043.85 $            2,594.85 $            5,499.36 $          11,244.45 $            6,565.55 $            6,031.15 $            4,912.76 $            6,182.45 $            4,218.95 $          40,231.27 $            3,608.95 $            3,041.44 $            1,581.93 $            1,468.48 $            2,294.55 $            7,138.72

Sex (M/F/U) F F M M F U M M F M F M M F F M M M F F M M M F M F F M F M M M M M M F F M F F M F M M M F F M M M F F M M M F M F M M M M F F F F M M F F M M F F F M F M F M F F M F M M F F M F F F F M M M M F F F F F F F F M F M F F F M M F F M F M F M M F M F F F F F F

Answer 1

Treat the Patients dataset (Excel) as a sample from a larger population. Assuming that the total charges variable is normally distributed, use a one-tail t test of hypothesis (α = 0.05) for the mean (σ unknown) to test the hypothesis that the population mean total charges is greater than $10,000.

Hypotheses are:

Following is the output of t test:

The p-value is: 1.0000

Since p-value is greater than 0.05 so we fail to reject the null hypothesis. That is we cannot conclude that the population mean total charges is greater than $10,000.

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Using the pooled variance t-test for the difference between two means, at the 0.05 level of significance, is there evidence that the mean age for male patients is different from the mean age for female patients? Be sure to provide the null and alternate hypotheses.

For this question need ages of males and females.