1)A relationship expert is interested in the relationship between divorce and general happiness. A sample of 1,212 individuals who reported their marital status as either "married" or "divorced" was selected and individuals in the two groups were asked to rate their general level of happiness (either "Not Too happy" or "Pretty/Very Happy"). The table below summarizes the data.
Group | Not Too Happy | Pretty/Very Happy | Total |
Divorced (Group 1) | 60 | 255 | 315 |
Married (Group 2) | 64 | 833 | 897 |
Calculate the test statistic of the test of the hypothesis that the proportion of divorced people who are "Pretty/Very Happy" is smaller than the proportion of married people who are "Pretty/Very Happy". Take all calculations toward the answer to four (4) decimal places.
1)__________
2)A relationship expert is interested in the relationship between divorce and general happiness. A sample of 1,212 individuals who reported their marital status as either "married" or "divorced" was selected and individuals in the two groups were asked to rate their general level of happiness (either "Not Too Happy" or "Pretty/Very Happy"). The table below summarizes the data.
Group | Not Too Happy | Pretty/Very Happy | Total |
Divorced (Group 1) | 60 | 255 | 315 |
Married (Group 2) | 64 | 833 | 897 |
Calculate the upper bound of the 95% confidence interval for the difference between the proportion of divorced and the proportion of married persons who are "Pretty/Very Happy." Take all calculations toward the answer to four (4) decimal places, and report your answer to three decimal places.
2)________
#1.
H0: p1 = p2
Ha: p1 < p2
n1 = 315
n2 = 897
p1cap = 255/315 = 0.8095
p2cap = 833/897 = 0.9287
pcap = (255 + 833)/(315+897) = 0.8977
SE = sqrt(0.8977*(1-0.8977)((1/315+1/897))
SE = 0.0198
Test statistics, z = (0.8095 - 0.9287)/0.0198
z = -6.0019
p-value = 0.0000
Reject the null hypothesis
Significant evidence to conclude that proportion of "Pretty/very
happy" of divorced individuals is less than "Pretty/very happy" of
married individuals.
#2.
z = 1.64
upper bound = (0.8095 - 0.9287) + 1.64*0.0198
upper bound = -0.0867
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