The proportion of left hand dpeople in the general population is about 40%.Suppose a random sample. of 36 people is observed.
What is the probability of obtaining 20 or less left handed people in your sample of 36?
Given : n=36 , p=0.40
Here , X has binomial distribution with parameter n and p.
Now , np=36*0.40=14.4>10 and n(1-p)=36*(1-0.40)=21.6>10
Therefore , use the normal approximation ,
Now ,
; From the standard normal probability distribution table
Therefore , the
probability of obtaining 20 or less left handed people in your sample of 36 is 0.9719
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