n |
s |
||
Men |
20 |
121.3 |
32.85 |
Women |
18 |
141.1 |
26.44 |
Interpret the results of the confidence interval in the context of the problem. Then answer the question “Is it plausible that the mean attitudes towards school and study habits between men and women are equal?” (use complete sentences and justify your answer) 5pts
Given a 90% confidence interval for the difference of mean attitude towards school and study habits between men and women is ( -36.07 , -3.532) . It does not include zero therefore SIGNIFICANT . THERE IS DIFFERENCE IN MEANS.
Testing for Equality of Variances
A F-test is used to test for the equality of variances. The following F-ratio is obtained:
FF=s1^2/s2^2=(32.85)^2/(26.44)^2
The critical values are FL=0.946 and FU=1.067, and since F=1.544, then the null hypothesis of equal variances is rejected.
Using the P-value approach: The p-value is p=0.0472, and since p=0.0472<0.1, it is concluded that the null hypothesis is rejected.
Conclusion: It is concluded that the null hypothesis Ho is rejected. Therefore, there is enough evidence to claim that population mean μ1 is different than μ2, at the 0.1 significance level.
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