Question

This is meant for R. AirPassengers is a time series giving the monthly totals (in thousands)...

This is meant for R. AirPassengers is a time series giving the monthly totals (in thousands) of international airline passengers, 1949 to 1960. We may convert the time series to a vector,x, with the assignment x <- as.vector(AirPassengers). Let the random variable X represent a random observation from the values in AirPassengers. Assume X has mean mu and standard deviation sigma and that there is no trend in the data and values are independent from one another. Think of x as a random sample from X.h) Calculate the critical value to be used to produce an 97% confidence interval for μ.#Note that this is a large sample so use a normal critical value. i) Find the lower boundary for a 97% confidence interval for μ. Incorrect: Your answer is incorrect. j) Find the upper boundary for a 97% confidence interval for μ. Incorrect: Your answer is incorrect. k) How long is the 97% confidence interval for μ? l) How many outliers does an R box plot of x show? 0 Many 2 -2 4 1 3

Homework Answers

Answer #1

x=as.vector(AirPassengers)

> x

[1] 112 118 132 129 121 135 148 148 136 119 104 118 115 126 141 135 125 149 170 170 158 133 114 140 145 150 178 163 172 178 199

[32] 199 184 162 146 166 171 180 193 181 183 218 230 242 209 191 172 194 196 196 236 235 229 243 264 272 237 211 180 201 204 188

[63] 235 227 234 264 302 293 259 229 203 229 242 233 267 269 270 315 364 347 312 274 237 278 284 277 317 313 318 374 413 405 355

[94] 306 271 306 315 301 356 348 355 422 465 467 404 347 305 336 340 318 362 348 363 435 491 505 404 359 310 337 360 342 406 396

[125] 420 472 548 559 463 407 362 405 417 391 419 461 472 535 622 606 508 461 390 432

>

> ## Median of X ##

> median(x)

[1] 265.5

>

> ## Maximum value of X ##

> max(x)

[1] 622

>

> ## Mean of X ##

> xbar=mean(x)

> xbar

[1] 280.2986

>

> ## 39th percentile ##

> p=quantile(x,0.39)

> p

39%

229

> ## Sample standard Deviation ##

> SD=sqrt(var(x))

> SD

[1] 119.9663

>

>

> ## interquartile RAnge ##

> iqr=IQR(x)

> iqr

[1] 180.5

>

>

> ## number of element in X ##

> e=length(x)

> e

[1] 144

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