The data below is your data set for your mini lab. For this
assignment, you are the researcher. You gave the facial recognition
lab to 40 students, 20 males and 20 females. The data set below
contains the number of correct hits for each subject. Complete the
calculations below based on the data provided.
Males 5 5 8 5 6 7 4 5 3 4 8 5 10 6 5 5 8 7 5 6
Females 9 8 7 7 9 8 8 8 9 10 7 9 8 9 7 9 8 7 9 7 .
Calculate the mean number of correct responses (hits) for male subjects. Round to the nearest hundreths place
2. Calculate the Standard Deviation (SD) of the correct reponses for male subjects. Round to the nearest hundreths place
3. Calculate the Standard Error of Mean (SEM) of correct responses for male subjects. Round to the nearest hundreths place.
4. Calculate the mean number of correct responses (hits) for female subjects. Round to the nearest hundreths place
5. Calculate the Standard Deviation (SD) of the correct reponses for female subjects. Round to the nearest hundreths place
6. Calculate the Standard Error of Mean (SEM) of correct responses for female subjects. Round to the nearest hundreths place.
7. Use a statistical software program or your favorite stats website and find the t value for an unpaired 2 sample t test using the data from the 2 groups, the males and females.
8. What is the degree of freedom associated with this t test.
9. The p value associated with the t value is
a. less than .05
b. greater than .05
c. I have no idea
10. Based on your calculations, would you reject the null
hypothes that there is no difference between males and females on
this recognition task?
a. Yes, I would reject the null hypothesis.
b. No, I would not reject the null hypothesis.
c. I have no idea.
MALE hits
1.) Mean -> 5.85
2.) Standard Deviation->
1.694418 |
3.) Standard error ->
0.378883 |
FEMALE hits
4.) Mean->
8.15 |
5.) Standard Deviation->
0.933302 |
6.) Standard Error->
0.208693 |
Find image with calculations of t tests
where degree of freedom is 19
treatment 1 is male
treatment 2 is females
t value for significance level .05 is -5.32
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