Question

1.) Assume that the data has a normal distribution and the number of observations is greater than fifty. Find the critical z value used to test a null hypothesis.

α = 0.08; H₁ is μ ≠ 3.24

A.)1.41

B.) 1.41 and -1.41

C.)1.75

D.) 1.75 and -1.75

2.) Express the confidence interval using the indicated format.

                                                  
Express the confidence interval (0.432, 0.52) in the form of ± E.

A.) 0.476 ± 0.044

B.) 0.476 ± 0.088

C.) 0.432 ± 0.044

D.)0.432 ± 0.088

Answer 1

1)

This is two tailed test.

Critical values at 0.08 significance level = 1.75 and -1.75

2)

Given confidence interval is ( 0.432 , 0.520)

Margin of error E = width of confidence interval / 2

E = ( 0.520 - 0.432) / 2 = 0.044

Sample proportion proportion = Upper limit - E = 0.520 - 0.044 = 0.476

Confidence interval in terms of E = 0.476 0.044