Question

(a) In an insurance company the average number of sick leaves for an employee is 0.5...

(a) In an insurance company the average number of sick leaves for an employee is 0.5 per month. The numbers of sick leaves in different months are independent. Under appropriate assumptions about the distribution, find the probability that the number of sick leaves for an employee is at least four days in a year. Write down and justify your assumptions.

(b) An insurance company has three different types of employees, with 100 people of each type. Find the probability that a random group of 20 employees will miss at least one type. You can keep your answer in raw form.

Math   Statistics-And-Probability   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
The mean number of sick days an employee takes per year is believed to be about...
The mean number of sick days an employee takes per year is believed to be about 10. Members of a personnel department do not believe this figure. They randomly survey 8 employees. The number of sick days they took for the past year are as follows: 12; 5; 13; 4; 11; 9; 8; 10. Let X = the number of sick days they took for the past year. Should the personnel team believe that the mean number is about 10?...
Suppose that a company finds that the mean number of sick days for their employees is...
Suppose that a company finds that the mean number of sick days for their employees is 5.5 days/year with a standard deviation of 2.4 days/year. What is the probability that a sample of 30 employees finds a mean of at least 6.5 days/year?
The mean number of sick days an employee takes per year is believed to be about...
The mean number of sick days an employee takes per year is believed to be about 10. Members of a personnel department do not believe this figure. They randomly survey 8 employees. The number of sick days they took for the past year are as follows: 11; 5; 13; 4; 10; 9; 7; 8. Let X = the number of sick days they took for the past year. Should the personnel team believe that the mean number is about 10?...
The average number of claims to an insurance company is 3 demands per day. a. Find...
The average number of claims to an insurance company is 3 demands per day. a. Find what is the probability that in a week there will be at least 5 days, 2 or 3 or 4 demands. b. Determine the probability that in a month, at least 15 days and at most 22 days, the number of demands is between 3 and 6 demands.
A company is interested in estimating μ, the mean number of days of sick leave taken...
A company is interested in estimating μ, the mean number of days of sick leave taken by its employees. Their statistician randomly selects 100 personnel files and notes the number of sick days taken by each employee. The sample mean is 12.2 days, and the sample standard deviation is 10 days. How many personnel files would the statistician have to select in order to estimate μ to within 2 days with a 99 percent confidence interval? Note: Sigma Unknown 136...
The mean number of sick days an employee takes per year is believed to be about...
The mean number of sick days an employee takes per year is believed to be about 10. Members of a personnel department do not believe this figure. They randomly survey 8 employees. The number of sick days they took for the past year are as follows: 10; 5; 15; 5; 9; 10; 6; 9. Let X = the number of sick days they took for the past year. Should the personnel team believe that the mean number is about 10?...
A company has ve employees on its health insurance plan. Each year, each employee independently has...
A company has ve employees on its health insurance plan. Each year, each employee independently has an 80% probability of no hospital admissions. If an employee requires one or more hospital admissions, the number of ad- missions is modeled by a geometric distribution with a mean of 1.50. The numbers of hospital admissions of different employees are mutually indepen- dent. Each hospital admission costs 20,000. Calculate the probability that the company's total hospital costs in a year are less than...
During contract negotiations, a company seeks to change the number of sick days employees may take,...
During contract negotiations, a company seeks to change the number of sick days employees may take, saying that the annual "average" is 7 days of absence per employee. The union negotiators counter that the "average" employee misses only 3 days of work each year. Explain how both sides might be correct, identifying the measure of center you think each side is using and why the difference may exist. Thank you.
A company is studying the number of monthly absences among its 125 employees. The following probability...
A company is studying the number of monthly absences among its 125 employees. The following probability distribution shows the likelihood that people were absent 0, 1, 2, 3, 4, or 5 days last month. Number of days absent 0 1 2 3 4 5    Probability 0.5 0.2 0.15 0.1 0.04   0.01 Is this a probability distribution? Why? What is the random variable? What is the probability that a randomly selected employee was absent for more than 3 days? What...
A company is studying the number of monthly absences among its 125 employees. The following probability...
A company is studying the number of monthly absences among its 125 employees. The following probability distribution shows the likelihood that people were absent 0, 1, 2, 3, 4, or 5 days last month. Number of days absent   Probability 0   0.5 1   0.2 2   0.15 3   0.1 4   0.04 5     0.01 Is this a probability distribution? Why? What is the random variable? What is the probability that a randomly selected employee were absent for more than 3 days? What is the...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT