An insurance for an appliance costs $52 and will pay $520 if the insured item breaks. The insurance company estimates that 2% of the insured items will break.
Let XX be the random variable that assigns to each outcome (item breaks, item does not break) the profit for the company. A negative value is a loss.
(a) Complete the table below.
X | 52 | -520 |
---|---|---|
p(x) | Answer | 0.02 |
(b) Calculate the expected profit for the company for each insurance policy. In other words, find the expected value of X.X. μX=μX=
(c) Find the variance of X.X. Var(X)=Var(X)=
(d) Find the standard deviation of X.X. σX=σX=
(a) as the sum of probability should be equal to 1 therefore Answer is
X | 52 | -520 |
---|---|---|
p(x) | 0.08 | 0.02 |
(b) the expected profit
(c) variance of
(d) standard deviation of XX is the square root of variance. Therefore,
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