The starting salaries of individuals with an MBA degree are normally distributed with a mean of $65,000 and a standard deviation of $15,000. What is the probability that a randomly selected individual with an MBA degree will have a starting salary of at least $50,000?
a. |
0.8772 |
|
b. |
0.7486 |
|
c. |
0.8293 |
|
d. |
0.8413 |
QUESTION 11
The starting salaries of individuals with an MBA degree are normally distributed with a mean of $65,000 and a standard deviation of $15,000. What is the lowest salary for those individuals with an MBA degree whose starting salary is in the top 40 percent?
a. |
$66,400 |
|
b. |
$63,750 |
|
c. |
$68,750 |
|
d. |
$72,600 |
ANSWER 1
The following information has been provided:
μ=65000, σ=15000
We need to compute Pr(X≥50000). The corresponding z-value needed to be computed is:
Therefore, we get that
The following is obtained graphically:
ANSWER 2
This is the closest answer to the real answer:
Using excel:
=NORM.INV(1-0.4,65000,15000)
= 68800.206547037 which is closest to 68,750
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