A researcher randomly sampled 50 graduates of an MBA program and recorded data concerning their starting salaries. Of primary interest to the researcher was the effect of gender on starting salaries. Analysis of the mean salaries of the females and males in the sample is given below. Female MBA graduate: sample mean= $52,500, population standard deviation= 12000, sample size = 25. Male MBA graduates: Sample mean= $56,000, population standard deviation = 13000, sample size = 25
Assuming that the populations are normally distributed, is there evidence of a difference in the average starting salary of the Male MBA graduates and the Female MBA graduates? Use a 0.05 level of significance. Show all details of the Answer
Answer)
Null hypothesis Ho : u1-u2 = 0
Alternate hypothesis Ha : u1-u2 not equal to 0
As the population s.d is known here we can use standard normal z table to conduct the test
Test statistics z = (u1-u2)/standard error
Standard error = √{(s1^2/n1)+(s2^2/n2)}
u1 = 52500, s1 = 12000, n1 = 25
u2 = 56000, s2 = 13000, n2 = 25
After substitution
Z = -0.99
From z table, P(z<-0.99) = 0.1611
But our test is two tailed so, P-Value is = 2*0.1611 = 0.3222
As the obtained P-Value is greater than the given significance level 0.05
We fail to reject the null hypothesis Ho
And we do not have enough evidenve to conclude that there is difference in starting average salary of mba male and female
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