Question

**Use the normal distribution to find a confidence
interval for a difference in proportions**

**p1-p2**

**given the relevant sample results. Assume the results
come from random samples.**

**A 99% confidence interval for**

**p1-p2**

**given that**

**p^1=0.76**

**with**

**n1=590**

**and**

**p^2=0.65**

**with**

**n2=340**

**Give the best estimate for**

**p1-p2**

**, the margin of error, and the confidence
interval.**

**Round your answer for the best estimate to two decimal
places and round your answers for the margin of error and the
confidence interval to three decimal places.**

**Best estimate :**

**Enter your answer; Best estimate**

**Margin of error :**

**Enter your answer; Margin of error**

**Confidence interval :**

**Enter your answer; Confidence interval, value
1**

Answer #1

**For the 99%
Confidence interval**

= 0.76 and 1 - = 0.24, n1 = 590

= 0.65 and 1 - = 0.35, n2 = 340

The Zcritical (2 tail) for = 0.01, is 2.576

(a) The Best Estimate for p1 - p2 = (-
) = 0.76 – 0.65 = **0.11**

(b) The Confidence Interval is given by (- ) ME, where

ME = **0.081**

(c)

The Lower Limit = 0.11 - 0.081 = 0.029 (Rounding to 3 decimal places)

The Upper Limit = 0.11 + 0.081 = 0.191 (Rounding to 3 decimal places)

**The 99%
Confidence Interval is 0.029 < p1 - p2 <
0.191**

Use the normal distribution to find a confidence interval for a
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Assume the results come from random samples.
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(Use ascending order. Type an integer or decimal rounded to
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Chapter 6, Section 1-CI, Exercise 011
Use the normal distribution to find a confidence interval for a
proportion p given the relevant sample results. Give the
best point estimate for p, the margin of error, and the
confidence interval. Assume the results come from a random
sample.
A 95% confidence interval for p given that p^=0.34 and
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Round your answer for the best point estimate to two decimal
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difference between population proportions p1 -
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(Use ascending order. Type an integer or decimal rounded to
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