A student wants to determine if the proportion of grey emus to brown emus is a constant throughout the population. She found the in 30 emu farms she surveyed, the proportion of grey emus to brown emus is 0.46. She wants to develop a 90% confidence interval.What is the lower limit of a 90% confidence interval for this proportion?
Solution :
Given that,
n = 30
Point estimate = sample proportion = = x / n = 0.46
1 - = 1 - 0.46 =0.54
At 90% confidence level
= 1 - 90%
= 1 - 0.90 =0.10
=0.10
Z
= Z0.10 = 1.28
Margin of error = E = Z / 2 * (( * (1 - )) / n)
= 1.28 (((0.46*0.54) / 30)
= 0.1165
A 90% confidence interval for population proportion p is ,
- E
0.46 - 0.1165
0.3435
The 90% confidence interval for the population proportion p is :lower limit 0.3435
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