Question

If the amount of liquor poured into a drink at a bar is known to be normally distributed with mean 1.5 ounces and standard deviation .25 ounce, what is the probability that a random sample of 36 such drinks will have a mean liquor content of less than 1.4 ounces?

Answer 1

Solution :

Given that ,

mean = = 1.5

standard deviation = = 0.25

n = 36

= 1.5

= / n = 0.25 / 36

P( < 1.4) = P(( - ) / < (1.4 - 1.5) / 0.25 / 36)

= P(z < -2.4)

= 0.0082

Probability = 0.0082