Question

The data show the chest size and weight of several bears. Find the regression equation, letting chest size be the independent (x) variable. Then find the best-predicted weight of a bear with a chest size of 48 inches. Is the result close to the actual weight of 538 pounds? Use a significance level of 0.05.

Chest_size_(inches) Weight_ (pounds)

36 296

56 570

50 501

39 353

49 487

42 385

What is the regression equation?

ModifyingAbove y with caretyequals=nothingplus+nothingx

(Round to one decimal place as needed.)

Answer 1

X	Y	XY	X^2	Y^2
36	296	10656	1296	87616
56	570	31920	3136	324900
50	501	25050	2500	251001
39	353	13767	1521	124609
49	487	23863	2401	237169
42	385	16170	1764	148225

Regression equation;

y = a = bx

From the above table and formula we get the value are as:

n	6
sum(XY)	121426.00
sum(X)	272.00
sum(Y)	2592.00
sum(X^2)	12618.00
sum(Y^2)	1173520.00

b	13.6497
a	-186.7842

y = -186.7842 + 13.6497x

when x = 48

y = -186.7842 + 13.6497 * 48

= 468.4014