Let m1 and m2 denote the true average ages (in years) of students at two different colleges. Assume both population distributions are normal with equal variances. Calculate and interpret a 99% confidence interval for m1 - m2 using the following data.
Sample Size | Sample Mean | Sample Standard Deviation | |
College 1 | 10 | 25 | 2 |
College 2 | 9 | 24 | 3 |
Group of answer choices
A) 99% C.I. is (-2.36, 4.36). The sample supports the claim that the two colleges` students have significantly different ages.
B) 99% C.I. is (-2.10, -0.316). The sample supports the claim that the two colleges` students have significantly different ages.
C) 99% C.I. is (-2.36, 4.36). The sample supports the claim that the two colleges` students do not have significantly different ages.
D) 99% C.I. is (-2.10, -0.316). The sample supports the claim that the two colleges` students do not have significantly different ages.
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