Determine the t-value in each of the cases.
(a) Find the t-value such that the area in the right tail is 0.25 with 9 degrees of freedom. nothing (Round to three decimal places as needed.)
(b) Find the t-value such that the area in the right tail is 0.05 with 16 degrees of freedom. nothing (Round to three decimal places as needed.)
(c) Find the t-value such that the area left of the t-value is 0.15 with 5 degrees of freedom. [Hint: Use symmetry.] nothing (Round to three decimal places as needed.)
(d) Find the critical t-value that corresponds to 95 % confidence. Assume 9 degrees of freedom.
Solution :
Given that,
a) Area = = 0.25
Right tail test
Degrees of freedom = df =9
t ,df = t0.25,9 = 0.703
t value = 0.703
b)
Area = = 0.05
Right tail test
Degrees of freedom = df = 16
t ,df = t0.05,16 = 1.746
t value = 1.746
c)
Area = = 0.15
Left tail test
Degrees of freedom = df = 5
t ,df = t0.15= -1.156
t value = -1.156
d) Degrees of freedom = df = 9
At 95% confidence level
= 1-0.95% =1-0.95 =0.05
/2
=0.05/ 2= 0.025
t/2,df
= t0.025,9 = 2.262
Critical t value = 2.262
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