QUESTION 1
Group Statistics |
||||
GROUP |
n |
Mean |
Std. Deviation |
|
AdbreakLength |
network 1 |
45 |
6.25 |
2.04 |
The test statistic has value TS= .
Testing at significance level α = 0.05, the rejection region
is:
less than_______ and greater than___________ (2 dec
places).
There (is evidence/is no evidence) to reject
the null hypothesis, H 0.
There (is sufficient/is insufficient) evidence
to suggest that there is a difference between the two population
means, μ 1 and μ 2.
ii) Estimate the difference in population means by
calculating a 95% confidence interval.
The difference between the population means, the mean of population
1, μ 1, minus the mean of population 2, μ 2,
is estimated to be between ________ and____________ .
a. |
The average length of advertising breaks sampled from network 1 are significantly shorter than the average length of advertising breaks sampled on network 2. |
|
b. |
There is no significant difference between the average length of advertising breaks on network 1 and the average length of advertising breaks on network 2. |
|
c. |
The average length of advertising breaks sampled from network 1 are significantly longer than the average length of advertising breaks sampled from network 2. |
|
d. |
The average length of advertising breaks on network 1 are significantly shorter than the average length of advertising breaks on network 2. |
|
e. |
There is no significant difference between the average length of advertising breaks sampled from network 1 and the average length of advertising breaks sampled from network 2. |
|
f. |
The average length of advertising breaks on network 1 are significantly longer than the average length of advertising breaks on network 2 |
Were any assumptions required in order for this inference to be valid?
a. |
Yes, the sample of network 1 ad-breaks must be independent of
the sample of network 2 ad-breaks. |
|
b. |
Yes, the sample of network 1 ad-breaks must be independent of
the sample of network 2 ad-breaks. |
|
c. |
No. The Central Limit Theorem applies, which states the sampling distribution is normal for any population distributions. |
|
d. |
Yes , each population must be normally distributed, i.e. the population of all ad-breaks shown on network 1 have lengths that must be normally distributed and the population of all ad-breaks shown on network 2 have lengths that must be normally distributed. |
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