QUESTION 1
Group Statistics 

GROUP 
n 
Mean 
Std. Deviation 

AdbreakLength 
network 1 
45 
6.25 
2.04 
The test statistic has value TS= .
Testing at significance level α = 0.05, the rejection region
is:
less than_______ and greater than___________ (2 dec
places).
There (is evidence/is no evidence) to reject
the null hypothesis, H _{0}.
There (is sufficient/is insufficient) evidence
to suggest that there is a difference between the two population
means, μ _{1} and μ _{2}.
ii) Estimate the difference in population means by
calculating a 95% confidence interval.
The difference between the population means, the mean of population
1, μ _{1}, minus the mean of population 2, μ _{2},
is estimated to be between ________ and____________ .
a. 
The average length of advertising breaks sampled from network 1 are significantly shorter than the average length of advertising breaks sampled on network 2. 

b. 
There is no significant difference between the average length of advertising breaks on network 1 and the average length of advertising breaks on network 2. 

c. 
The average length of advertising breaks sampled from network 1 are significantly longer than the average length of advertising breaks sampled from network 2. 

d. 
The average length of advertising breaks on network 1 are significantly shorter than the average length of advertising breaks on network 2. 

e. 
There is no significant difference between the average length of advertising breaks sampled from network 1 and the average length of advertising breaks sampled from network 2. 

f. 
The average length of advertising breaks on network 1 are significantly longer than the average length of advertising breaks on network 2 
Were any assumptions required in order for this inference to be valid?
a. 
Yes, the sample of network 1 adbreaks must be independent of
the sample of network 2 adbreaks. 

b. 
Yes, the sample of network 1 adbreaks must be independent of
the sample of network 2 adbreaks. 

c. 
No. The Central Limit Theorem applies, which states the sampling distribution is normal for any population distributions. 

d. 
Yes , each population must be normally distributed, i.e. the population of all adbreaks shown on network 1 have lengths that must be normally distributed and the population of all adbreaks shown on network 2 have lengths that must be normally distributed. 
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