Question

summary for marriages

Mean	3407.94
Median	2364.00
Standard Deviation	3988.42
Minimum	136.00
Maximum	21451.00

n=52

Determine if there is sufficient evidence to conclude the average amount of marriages is greater or equal to 9000 in the United States and territories at the .05 level of significance

1. Clearly state a null and alternative hypothesis
2. Give the value of the test statistic
3. Report the P-Value
4. Clearly state your conclusion (Reject the Null or Fail to Reject the Null)
5. Explain what your conclusion means in context of the data.

Answer 1

Claim:- average amount of marriages is greater or equal to 9000 in the United States and territories

Null hypothesis

Alternate hypothesis

We will use t distribution because population standard deviation is unknown.

test statistic =

degree of freedom = n-1 = 52 - 1 =51

In t distribution table, checking df value in the left most column and t value in the row, we get

p value = 0.0000

We can reject the Ho as the p value is less than 0.05 significance level and the result is significant

Therefore, we can say that we have sufficient evidence to warrant that the rejection of claim that average amount of marriages is greater or equal to 9000 in the United States and territories.