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The following two-way table of counts summarizes whether respondents smoked or not and whether they have...

The following two-way table of counts summarizes whether respondents smoked or not and whether they have had ever divorced or not for persons who had ever been married.

Ever Divorced?
Smoke? Yes No
Yes 290 204
No 436 455

Among those who smoked, what percentage has ever been divorced? [Answer to 2 decimal places. Do not type % symbol in the box.]  %

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Among those who has ever been divorced, what percentage smoked? [Answer to 2 decimal places. Do not type % symbol in the box.]  %

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Next we intend to test if smoking habits and being divorced are related or not.
What is the expected frequency of smoker and ever being divorced? [Answer to 2 decimal places.]

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What is the expected frequency of smoker and never being divorced? [Answer to 2 decimal places.]

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What is the expected frequency of non-smoker and ever being divorced? [Answer to 2 decimal places.]

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What is the expected frequency of non-smoker and never being divorced? [Answer to 2 decimal places.]

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To test independence between smoking habits and being divorced, what is the value of chi-square test statistic? [Answer to 3 decimal places.]

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Suppose we are testing:

Null hypothesis: smoking habit and ever being divorced are not related,
against
Alternative hypothesis: smoking habit and ever being divorced are related.

If the p-value associated to the ch-square test-statistics is 0 and the level of significance is 5%, what will be your conclusion?
Do not reject null hypothesis
Not enough information to reach a decision
Reject null hypothesis

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