H0: p = 0.5
Ha: p > 0.5
Sample proportion = 72 / 123 = 0.5854
Test statistics
z = - p / sqrt(p(1-p)/n)
= 0.5854 - 0.5 / sqrt( 0.5 * 0.5 / 123)
= 1.89
This is test statistics value.
p-value = P( Z > z)
= P( Z > 1.89)
= 1 - p( Z < 1.89)
= 1 - 0.9706
= 0.0294
Since p-value < 0.05 significance level, we have sufficient evidence to reject H0.
We conclude at 0.05 level that we have enough evidence to support the claim.
Get Answers For Free
Most questions answered within 1 hours.