SSTR = 6,750  H_{0}: μ_{1}=μ_{2}=μ_{3}=μ_{4} 
SSE = 8,000  H_{a}: at least one mean is different 
n_{T} = 20 
Refer to Exhibit 1011. The null hypothesis
Question 15 options:
should be rejected 

should not be rejected 

was designed incorrectly 

None of these alternatives is correct. 
Given that
SSTR = 6,750  H_{0}: μ_{1}=μ_{2}=μ_{3}=μ_{4} 
SSE = 8,000  H_{a}: at least one mean is different 
n_{T} = 20 
F statistic = [SSTR/df(R)]/[SSE/df(E)]
setting SSTR = 6750, df(R) = number of categories  1 = 41 = 3, SSE = 8000 and df(E) = nT  number of categories = 204 = 16
setting the values, we get
F statistic = [6750/3]/[8000/16]
= 2250/500
= 4.5
p value = F.DIST.RT(x,df(R),df(E))
= F.DIST.RT(4.5,3,16)
= 0.018
So, p value is less than 0.05 significance level
Therefore, null hypothesis should be rejected
option A
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